**Contents**show

## What is the probability of rolling a sum of 8 with two dice?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

7 | 6 | 16.67% |

8 | 5 |
13.89% |

9 | 4 | 11.11% |

10 | 3 | 8.33% |

## What is the probability that the sum is 8 when throwing a dice given that the first die shows a 3?

The total number of ways to roll an 8 with 3 dice is therefore 21, and the probability of rolling an 8 is **21/216**, which is less than 5/36.

## What is the probability of rolling an 8?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

7 | 6/36 (16.667%) |

8 | 5/36 (13.889%) |

9 | 4/36 (11.111%) |

10 | 3/36 (8.333%) |

## When a pair of dice is rolled what is the probability that the sum of the dice is 10 given that the outcome is not 6?

If you consider the chart on the webpage given, there are 36 combination of rolls you can get from two dice. When you consider the sum being 10, there are only 3 combinations. So, the probability of getting a 10 would be **3/36 = 1/12**. But, then, of those 3 combinations, only 2 of them have a 4.

## What is the probability that when two dice are rolled the sum of the numbers on the two dice is 7?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## What is the probability of rolling one die and getting a 7?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## What is the probability formula?

In general, the probability is the ratio of the number of favorable outcomes to the total outcomes in that sample space. It is expressed as, Probability of an **event P(E) = (Number of favorable outcomes) ÷ (Sample space)**.

## When a pair of dice is rolled what is the probability that the sum of the dice is given that the outcome is not?

The probability of any number occurring is 1 in 36 or 1 / 36. Then the probability an 8 will not occur is: 1 – 5 / 36 or **31 / 36**. I could have added up all of the ways an 8 could not occur such as: 1 / 36 + 1 / 36 … 1 / 36 = 31 / 36, but that is the hard way.